21. Multiple Integrals in Curvilinear Coordinates

b. Integrating in Cylindrical Coordinates

The extension of triple integrals to cylindrical coordinates is very similar to the extension of double integrals to polar coordinates. We will break up the region of integration RR into subregions RkR_k which are cylindrical grid cells. So we need to know the volume of these cells.

1. Grid Cells

A cylindrical box is similar to the polar rectangle except there is an additional zz coordinate.

The cells look like a tower whose base is a polar grid cell. The base is marked off by two radial lines and two pieces of circles, and then this area is extended upwards to the value of zz.

A cylindrical box or cylindrical grid cell is a region of the form: r1rr2θ1θθ2andz1zz2 r_1 \le r \le r_2 \quad \theta_1 \le \theta \le \theta_2 \quad \text{and} \quad z_1 \le z \le z_2 See the figure at the right. The coordinate center of the cell is at: rˉ=r1+r22θˉ=θ1+θ22andzˉ=z1+z22 \bar{r}=\dfrac{r_1+r_2}{2} \quad \bar{\theta}=\dfrac{\theta_1+\theta_2}{2} \quad \text{and} \quad \bar{z}=\dfrac{z_1+z_2}{2} and the coordinate dimensions of the cell are: Δr=r2r1Δθ=θ2θ1andΔz=z2=z1 \Delta r=r_2-r_1 \quad \Delta\theta=\theta_2-\theta_1 \quad \text{and} \quad \Delta z=z_2=z_1

3dcylgrid

Since the base of the box is a polar rectangle of area ΔA=rˉΔrΔθ\Delta A=\bar{r}\,\Delta r\Delta\theta and the height is Δz\Delta z, we conclude:

Volume of a Cylindrical Box
The volume of a cylindrical box is: ΔV=rˉΔrΔθΔz \Delta V=\bar{r}\,\Delta r\Delta\theta\Delta z

In the limit as Δr\Delta r, Δθ\Delta\theta and Δz\Delta z get small, Δr\Delta r becomes drdr, Δθ\Delta\theta becomes dθd\theta, Δz\Delta z becomes dzdz and ΔV\Delta V becomes dVdV. Consequently:

Differential of Volume in Cylindrical Coordinates
The cylindrical differential of volume is: dV=rdrdθdz dV=r\,dr\,d\theta\,dz

Memorize this!

We will see how the differential of volume is used in integrals on the next page.

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